孝感城區每天清晨都要進行灑水，若一輛灑水車空車質量6t，水罐容積5m3.裝滿水後，車輪與地面的總接觸面積為0....

問題詳情：

孝感城區每天清晨都要進行灑水，若一輛灑水車空車質量6t，水罐容積5m3.裝滿水後，車輪與地面的總接觸面積為0.5m2.（ g 取10N/kg，ρ水=1.0×103kg/m3）。

問：

（1）該車最多能裝水的質量為多少？

（2）灑完一半水時，灑水車對地面的壓強為多少？

（3）若罐內水深1.5m，則水對罐底的壓強為多少？

【回答】

（1）m=ρ水V=1.0×103kg/m3×5 m3=5×103kg··························································· (1分)

（2）F=G車+G水=（6×103+2.5×103）kg×10N/kg=8.5×104N····························· (1分)

P=F/S=8.5×104N/0.5m2=1.7×105Pa························································· (1分)

（3）P=ρ水gh=1.0×103kg/m3×10N/kg×1.5m=1.5×104Pa···································· (1分)

知識點：壓強和浮力單元測試

題型：計算題