孝感城区每天清晨都要进行洒水，若一辆洒水车空车质量6t，水罐容积5m3.装满水后，车轮与地面的总接触面积为0....

问题详情：

孝感城区每天清晨都要进行洒水，若一辆洒水车空车质量6t，水罐容积5m3.装满水后，车轮与地面的总接触面积为0.5m2.（ g 取10N/kg，ρ水=1.0×103kg/m3）。

问：

（1）该车最多能装水的质量为多少？

（2）洒完一半水时，洒水车对地面的压强为多少？

（3）若罐内水深1.5m，则水对罐底的压强为多少？

【回答】

（1）m=ρ水V=1.0×103kg/m3×5 m3=5×103kg··························································· (1分)

（2）F=G车+G水=（6×103+2.5×103）kg×10N/kg=8.5×104N····························· (1分)

P=F/S=8.5×104N/0.5m2=1.7×105Pa························································· (1分)

（3）P=ρ水gh=1.0×103kg/m3×10N/kg×1.5m=1.5×104Pa···································· (1分)

知识点：压强和浮力单元测试

题型：计算题