问题详情:
孝感城区每天清晨都要进行洒水,若一辆洒水车空车质量6t,水罐容积5m3.装满水后,车轮与地面的总接触面积为0.5m2.( g 取10N/kg,ρ水=1.0×103kg/m3)。
问:
(1)该车最多能装水的质量为多少?
(2)洒完一半水时,洒水车对地面的压强为多少?
(3)若罐内水深1.5m,则水对罐底的压强为多少?
【回答】
(1)m=ρ水V=1.0×103kg/m3×5 m3=5×103kg··························································· (1分)
(2)F=G车+G水=(6×103+2.5×103)kg×10N/kg=8.5×104N····························· (1分)
P=F/S=8.5×104N/0.5m2=1.7×105Pa························································· (1分)
(3)P=ρ水gh=1.0×103kg/m3×10N/kg×1.5m=1.5×104Pa···································· (1分)
知识点:压强和浮力单元测试
题型:计算题