問題詳情:
已知:31=3,32=9,33=27,34=81,35=243,36=729…,設A=2(3+1)(32+1)(34+1)+1,則A的個位數字是 .
【回答】
1.【解答】解:A=(3﹣1)(3+1)(32+1)(34+1)+1
=(32﹣1)(32+1)(34+1)+1
=(34﹣1)(34+1)+1
=+1
=364﹣1+1
=364,
觀察已知等式,個位數字以3,9,7,1循環,
則A的個位數字是1,
故*爲:
知識點:整式的乘法
題型:填空題