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“ABD”簡單造句,ABD造句子

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Research on Entities Movement Mechanism of ABD-based Combat Simulation Model;

Asset-based development (ABD) is a large concept and is worthy of its own series of articles.

The ABD is ready for analysis in 3 minutes with run-to-run cycle times of 5 minutes or less per sample.

In much the same way, the roles and use-case activities associated with ABD and the asset lifecycle are independent from, but related to, roles and activities of RUP.

ABD and MDD are not mutually exclusive.

Results Acid-base disturbance (ABD) was found in 115 of the 126 patients (91.3%).

ABD can benefit both sides by reusing previous solutions (so-called assets) to solve recurring and emerging problems.

Asset-based development (ABD) is a key mechanism for addressing the ever-increasing challenges in the cost and efficiency of software production and delivery.

客户也可以提供反饋給資產生產和管理階段,這有助於ABD流程成為一個自我完善的循環。

Access the system metadata needed by the ABD process.

一個成功的ABD集成必須結合兩個API的功能。

ABD提供了整個組織內的一致*(由於使用了相同的資產,因此相同的需求導致相同的設計決策)。

Figure 4: Mapping the various ABD workflows across several projects.

BDD brings together the techniques of Model Driven Development (MDD) and ABD as a key governance aspect.

簡而言之,ABD工作流程可以被描繪在RUP階段,就像圖3中所示的那樣,而且還可以應用於跨項目的邊界處,圖4反映了這一點。

Expression and Effects of ABD Protein on the K562 and HL60 Cell;

ABD造句

ABD和MDD並不是互斥的。

To summarize, the ABD workflows can be mapped on to the RUP phases as shown in Figure 3, and are applicable across project boundaries, as shown in Figure 4.

ABD流程包含四個關鍵階段:資產識別、資產生產、資產管理和資產消耗。

SOA為應用那些描述資產所涉及的種類和類型的MDD和ABD提供了初步的解決方案架構。

THE LAGRANGIAN ABD EBERGT FORMULA FOR A SYSTEM OF PARTICLES IN THE ROTATION FRAME OF REFERENCE

The ABD process contains four key stages: asset identification, asset production, asset management, and asset consumption.

Tags:造句 ABD
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如圖,在矩形ABCD中,AB=3,將△ABD沿對角線BD對摺,得到△EBD,DE與BC交於點F,∠ADB=30... 如圖所示,平面四邊形ABCD中,AB=AD=CD=1,BD=,BD⊥CD,將其沿對角線BD折成四面體ABCD,... 如圖,平行四邊形ABCD中,AB⊥BD,沿BD將△ABD折起,使面ABD⊥面BCD,連接AC,則在四面體ABC... 如圖6所示,梯形ABCD中,AD∥BC,∠C=90°,且AB=AD,連結BD,過A點作BD的垂線,交BC於E,... 如圖,在四邊形ABCD中,DC∥AB,CB⊥AB,AB=AD,CD=AB,點E、F分別為AB.AD的中點,則△... 如圖,已知四稜錐P-ABCD中,底面ABCD是直角梯形,AD//BC,BC=2AD,AD⊥CD,PD⊥平面AB... 如圖,在四邊形ABCD中,AB=AD,CB=CD,對角線AC,BD相交於點O,下列結論中:①∠ABC=∠ADC... 在菱形ABCD中,A=60°,AB=2,將△ABD沿BD折起到△PBD的位置,若二面角 P-BD-C的大小為1... 如圖,∠ADC=∠ABC=90°,AD=AB,有下列結論:①DC=BC;②AC⊥BD;③DE=BE;④∠ACD... 在四邊形ABCD中,對角線AC、BD相交於點O,給出下列四組條件:①AB∥CD,AD∥BC;②AB=CD,AD... 下列不屬於二倍體產生的配子基因型的是(  ) A.AbDB.AbdC.AaBdD.ABD 如圖,△BCD是等邊三角形AB=AD,∠BAD=90°,將△BCD沿BD摺疊到△BC′D的位置,使得AD⊥C′...  如圖在四稜錐P-ABCD中,PA⊥底面ABCD,∠DAB為直角,AB∥CD,AD=CD=2AB,E、F分別為... 如圖:直角梯形ABCD中,AD∥BC,AB⊥BC,AD=2,BC=3,將腰CD以D為中心逆時針旋轉90°至ED... 如圖(1),在直角梯形ABCD中,AD∥BC,∠ABC=90°,AB=BC=2,AD=6,CE⊥AD於點E,把...
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四邊形ABCD中,對角線AC、BD相交於點O,給出下列四組條件:①AB∥CD,AD∥BC;②AB=CD,AD=... 將基因型為AaBbCcDD和AABbCcDd的向日葵雜交,按自由組合定律,後代中基因型為AABBCCDd的個體... 如圖,D為∠BAC的外角平分線上一點並且滿足BD=CD,∠DBC=∠DCB,過D作DE⊥AC於E,DF⊥AB交... 如圖,在四稜錐P﹣ABCD中,PD⊥平面ABCD,底面ABCD是菱形,∠BAD=60°,AB=2,PD=,O為... 如圖,長方形ABCD中,∠DAB=∠B=∠C=∠D=90°,AD=BC=8,AB=CD=17.點E為*線DC上... 現有兩個邊長不等的正方形ABDC和abdc,如圖所示,且Aa、Bb、Cc、Dd間距相等。在AB、AC、CD、D...   如圖,在四稜錐P-ABCD中,底面ABCD是梯形,AB//CD,PD丄平面,BD⊥DC,PD=BD=DC=... 如圖①,在直角梯形ABCD中,AD∥BC,∠BAD= ,AB=BC=AD=,E是AD的中點,O是AC與BE的交... 如圖,BD為四邊形ABCD的對角線,BC=AD,∠A=∠CBD,∠ABD=120°,AB=3,CD=,則BC的... 如圖,在四邊形ABCD中,DC∥AB,CB⊥AB,AB=AD,CD=AB,點E、F分別為AB、AD的中點,則△... 如圖,在四邊形ABCD中,AB=BC,對角線BD平分∠ABC,P是BD上一點,過點P作PM⊥AD,PN⊥CD,... 如圖,四稜錐P-ABCD中,側面PAD為等邊三角形且垂直於底面ABCD,AB=BC=AD,∠BAD=∠ABC=... 基因型為DDBb的個體產生的配子,其基因型是(  )A.DB和DB B.Db和Db C.DD和Bb D.Db和... 現有兩個邊長不等的正方形ABCD和abcd,如圖所示,且Aa、Bb、Cc、Dd間距相等。在AB、AC、CD、D... 如圖,四邊形ABCD中,AB=AD=CD=1,BD=,BD⊥CD.將四邊形ABCD沿對角線BD折成四面體A′­...